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Popular >

-x^2+6x-8<= 0

Solution

- x^{2} + 6 x - 8 \leq 0

Solution

x \leq 2 or x \geq 4

+1

Interval Notation

(- \infty, 2] \cup [4, \infty)

Solution steps

- x^{2} + 6 x - 8 \leq 0

Factor

- x^{2} + 6 x - 8 : - (x - 2) (x - 4)

- (x - 2) (x - 4) \leq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x - 2) (x - 4)) (- 1) \geq 0 \cdot (- 1)

Simplify

(x - 2) (x - 4) \geq 0

Identify the intervals

x \leq 2 or x \geq 4

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Frequently Asked Questions (FAQ)

What is -x^2+6x-8<= 0 ?
The solution to -x^2+6x-8<= 0 is x<= 2\lor x>= 4