What is expand-((t^2+t)x+6x)/2 ?

The solution to expand-((t^2+t)x+6x)/2 is -(t^2x)/2-(tx)/2-3x

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expand-((t^2+t)x+6x)/2

expand

- \frac{( t ^{2} + t ) x + 6 x}{2}

- \frac{t ^{2} x}{2} - \frac{t x}{2} - 3 x

Solution steps

- \frac{( t ^{2} + t ) x + 6 x}{2}

Expand

(t^{2} + t) x + 6 x : t^{2} x + t x + 6 x

= - \frac{t ^{2} x + t x + 6 x}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{t ^{2} x + t x + 6 x}{2} = - (\frac{t ^{2} x}{2}) - (\frac{t x}{2}) - (\frac{6 x}{2})

= - (\frac{t ^{2} x}{2}) - (\frac{t x}{2}) - (\frac{6 x}{2})

Remove parentheses:

(a) = a

= - \frac{t ^{2} x}{2} - \frac{t x}{2} - \frac{6 x}{2}

Divide the numbers:

\frac{6}{2} = 3

= - \frac{t ^{2} x}{2} - \frac{t x}{2} - 3 x

a c (er + f) + a d + b

\frac{5}{( a + 3 ) ( h + a + 3 )}

(2 + 3 i) (4 + i)^{''}

(3 x - 1) (x + d x)

(b + e + f)^{5}

What is expand-((t^2+t)x+6x)/2 ?
The solution to expand-((t^2+t)x+6x)/2 is -(t^2x)/2-(tx)/2-3x