What is expand l(e^2(t-3)cos(t-3)) ?

The solution to expand l(e^2(t-3)cos(t-3)) is e^2ltcos(t-3)-3e^2lcos(t-3)

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expand l(e^2(t-3)cos(t-3))

expand

l (e^{2} (t - 3) cos (t - 3))

e^{2} lt cos (t - 3) - 3 e^{2} l cos (t - 3)

Solution steps

l (e^{2} (t - 3) cos (t - 3))

Remove parentheses:

(a) = a

= l e^{2} (t - 3) cos (t - 3)

= e^{2} l cos (t - 3) (t - 3)

Apply the distributive law:

a (b - c) = ab - a c

a = l e^{2} cos (t - 3), b = t, c = 3

= l e^{2} cos (t - 3) t - l e^{2} cos (t - 3) \cdot 3

= e^{2} lt cos (t - 3) - 3 e^{2} l cos (t - 3)

\frac{( b + x ) ^{4}}{4}

(x + 1)^{5} e^{3 x^{2}}

, (5 a^{2} - 2 b + c^{3}) (3 x - 2 y - 5 z + 2)

\frac{d G - G ^{2} d H}{G ( 1 + G H )}

What is expand l(e^2(t-3)cos(t-3)) ?
The solution to expand l(e^2(t-3)cos(t-3)) is e^2ltcos(t-3)-3e^2lcos(t-3)