What is expand 4ln(x^2+2)(2x-1) ?

The solution to expand 4ln(x^2+2)(2x-1) is 8xln(x^2+2)-4ln(x^2+2)

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expand 4ln(x^2+2)(2x-1)

expand

4 ln (x^{2} + 2) (2 x - 1)

8 x ln (x^{2} + 2) - 4 ln (x^{2} + 2)

Solution steps

4 ln (x^{2} + 2) (2 x - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = 4 ln (x^{2} + 2), b = 2 x, c = 1

= 4 ln (x^{2} + 2) \cdot 2 x - 4 ln (x^{2} + 2) \cdot 1

= 4 \cdot 2 x ln (x^{2} + 2) - 4 \cdot 1 \cdot ln (x^{2} + 2)

Simplify

4 \cdot 2 x ln (x^{2} + 2) - 4 \cdot 1 \cdot ln (x^{2} + 2) : 8 x ln (x^{2} + 2) - 4 ln (x^{2} + 2)

= 8 x ln (x^{2} + 2) - 4 ln (x^{2} + 2)

\frac{d}{d y} ((x) (2 y^{2} x - 3))

\frac{1}{2 ( 3 y ^{5} - 1 )}

\frac{( x + 1 )}{2 ( x - 1 )}

\frac{2 ( 1 + x ) 1 + x}{3}

(x + 1) (x + 4 = x^{2} + 14)

What is expand 4ln(x^2+2)(2x-1) ?
The solution to expand 4ln(x^2+2)(2x-1) is 8xln(x^2+2)-4ln(x^2+2)