What is expand (du=-1dv) 1/(-1) ?

The solution to expand (du=-1dv) 1/(-1) is -du=dv

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expand (du=-1dv) 1/(-1)

expand

(d u = - 1 d v) \frac{1}{- 1}

- d u = d v

Solution steps

(d u = - 1 \cdot d v) \frac{1}{- 1}

= \frac{1}{- 1} (= d u - 1 \cdot d v)

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{1}{- 1}, b = d u =, c = 1 \cdot d v

\frac{1}{- 1} d u = - \frac{1}{- 1} \cdot 1 \cdot d v

\frac{1}{- 1} d u = - 1 \cdot \frac{1}{- 1} d v

Simplify

\frac{1}{- 1} d u = - 1 \cdot \frac{1}{- 1} d v : - d u = d v

- d u = d v

(u + 1) u d u

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\frac{π \cdot 25 ( x - 11 )}{3}

What is expand (du=-1dv) 1/(-1) ?
The solution to expand (du=-1dv) 1/(-1) is -du=dv