What is expand-2(2x-1+1=17-4x) ?

The solution to expand-2(2x-1+1=17-4x) is -4x=17+8x

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expand-2(2x-1+1=17-4x)

expand

- 2 (2 x - 1 + 1 = 17 - 4 x)

- 4 x = 17 + 8 x

Solution steps

- 2 (2 x - 1 + 1 = 17 - 4 x)

= - 2 (2 x - 1 + 1 \cdot 17 = - 4 x)

Distribute parentheses

(- 2) \cdot 2 x + (- 2) (- 1) + (- 2) \cdot 1 = 17 + (- 2) (- 4 x)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

- 2 \cdot 2 x + 2 \cdot 1 - 2 \cdot 1 = 17 + 2 \cdot 4 x

Simplify

- 2 \cdot 2 x + 2 \cdot 1 - 2 \cdot 1 = 17 + 2 \cdot 4 x : - 4 x = 17 + 8 x

- 4 x = 17 + 8 x

(2 + 6 i,) (- 4 + 3 i,)

((x - 2) (x - 3)) + (x^{2} - 1)

3 (x - 1 = 30)

\frac{4 x ^{2}}{( x + 1 ) ^{2} ( x - 1 )}

- \frac{x + 1}{( y - 1 ) ^{2}}

What is expand-2(2x-1+1=17-4x) ?
The solution to expand-2(2x-1+1=17-4x) is -4x=17+8x