What is expand ln(q)(-1/a-1) ?

The solution to expand ln(q)(-1/a-1) is -(ln(q))/a-ln(q)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ln(q)(-1/a-1)

expand

ln (q) (- \frac{1}{a} - 1)

- \frac{ln ( q )}{a} - ln (q)

Solution steps

ln (q) (- \frac{1}{a} - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = ln (q), b = - \frac{1}{a}, c = 1

= ln (q) (- \frac{1}{a}) - ln (q) \cdot 1

Apply minus-plus rules

+ (- a) = - a

= - \frac{1}{a} ln (q) - 1 \cdot ln (q)

Simplify

- \frac{1}{a} ln (q) - 1 \cdot ln (q) : - \frac{ln ( q )}{a} - ln (q)

= - \frac{ln ( q )}{a} - ln (q)

(- 3 x - 2) (\cdot + 2)

- \frac{5}{81} (9 e^{9 x} x - e^{9 x})

A^{'} (t) (π (2 - t)^{2})

(x^{3}) (x^{2})

(- \frac{3 ( x - 2 )}{x + 1}) + 2

What is expand ln(q)(-1/a-1) ?
The solution to expand ln(q)(-1/a-1) is -(ln(q))/a-ln(q)