What is expand (1-sec(x))(1+sec(x))' ?

The solution to expand (1-sec(x))(1+sec(x))' is (1+sec(x))'-sec(x)(1+sec(x))'

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expand (1-sec(x))(1+sec(x))'

expand

(1 - sec (x)) (1 + sec (x))^{'}

(1 + sec (x))' - sec (x) (1 + sec (x))'

Solution steps

(1 - sec (x)) (1 + sec (x))^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (1 + sec (x))^{'}, b = 1, c = sec (x)

= (1 + sec (x))^{^{'}} 1 - (1 + sec (x))^{^{'}} sec (x)

= 1 (1 + sec (x))^{^{'}} - sec (x) (1 + sec (x))^{^{'}}

Multiply:

1 (1 + sec (x))^{'} = (1 + sec (x))^{'}

= (1 + sec (x))^{^{'}} - sec (x) (1 + sec (x))^{^{'}}

π (2 x + 2 y)

\frac{x ( y - x )}{y}

\frac{x - 5 ( x + 4 + 3 )}{x + 13}

\frac{x ^{2} - x - 2}{( x - 1 ) ( x - 3 )}

(\frac{2 x + 5}{4})^{2}

What is expand (1-sec(x))(1+sec(x))' ?
The solution to expand (1-sec(x))(1+sec(x))' is (1+sec(x))'-sec(x)(1+sec(x))'