What is expand e(x-3)(x^2+2)' ?

The solution to expand e(x-3)(x^2+2)' is ex(x^2+2)'-3e(x^2+2)'

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expand e(x-3)(x^2+2)'

expand

e (x - 3) (x^{2} + 2)^{'}

e x (x^{2} + 2)' - 3 e (x^{2} + 2)'

Solution steps

e (x - 3) (x^{2} + 2)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = e (x^{2} + 2)^{'}, b = x, c = 3

= e (x^{2} + 2)^{^{'}} x - e (x^{2} + 2)^{^{'}} 3

= e x (x^{2} + 2)^{^{'}} - 3 e (x^{2} + 2)^{^{'}}

- h^{2 + (3 R - h) (2 h)}

(1 - x - x^{2})^{7}

\frac{( x - 2 ) x}{( x + 3 ) \cdot 2}

(e^{x} + 1) e^{x} + 2

(y^{2} + 1) d x + (2 x y + y e^{y}) d y

What is expand e(x-3)(x^2+2)' ?
The solution to expand e(x-3)(x^2+2)' is ex(x^2+2)'-3e(x^2+2)'