What is expand (x'-x'')^2 ?

The solution to expand (x'-x'')^2 is (x')^2-2x'x''+(x'')^2

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expand (x'-x'')^2

expand

(x^{'} - x^{''})^{2}

(x')^{2} - 2 x' x'' + (x'')^{2}

Solution steps

(x^{'} - x^{''})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = x^{'}, b = x^{''}

= (x^{^{'}})^{2} - 2 x^{^{'}} x^{^{''}} + (x^{^{''}})^{2}

(cos (x) + sin (x)) (2, x)

12 (2 x + 4 = 48)

\frac{x ^{2}}{( 1 + x ) ( 1 - x )}

\frac{3 \cdot ( 5 ^{n} - 1 )}{4}

(6 x - 4 y = 2) \frac{3}{2}

What is expand (x'-x'')^2 ?
The solution to expand (x'-x'')^2 is (x')^2-2x'x''+(x'')^2