What is expand (2x+1)e^{3x^2+3x} ?

The solution to expand (2x+1)e^{3x^2+3x} is 2e^{3x^2+3x}x+e^{3x^2+3x}

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expand (2x+1)e^{3x^2+3x}

expand

(2 x + 1) e^{3 x^{2} + 3 x}

2 e^{3 x^{2} + 3 x} x + e^{3 x^{2} + 3 x}

Solution steps

(2 x + 1) e^{3 x^{2} + 3 x}

= e^{3 x^{2} + 3 x} (2 x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{3 x^{2} + 3 x}, b = 2 x, c = 1

= e^{3 x^{2} + 3 x} \cdot 2 x + e^{3 x^{2} + 3 x} \cdot 1

= 2 e^{3 x^{2} + 3 x} x + 1 \cdot e^{3 x^{2} + 3 x}

Multiply:

1 \cdot e^{3 x^{2} + 3 x} = e^{3 x^{2} + 3 x}

= 2 e^{3 x^{2} + 3 x} x + e^{3 x^{2} + 3 x}

\frac{10 ( s + 1 )}{s ( s ^{2} + s + 10 )}

\frac{d}{d x} ((θ) (3 t^{4} - 2 t^{3}))

\frac{d}{d t} ((q (t)) (76 - 25 t))

\frac{( 4 - y ) x}{100 + ( 4 - y ) x}

t (5, - 15)

What is expand (2x+1)e^{3x^2+3x} ?
The solution to expand (2x+1)e^{3x^2+3x} is 2e^{3x^2+3x}x+e^{3x^2+3x}