What is expand (1,-2,1)(x+2y-z+3=0) ?

The solution to expand (1,-2,1)(x+2y-z+3=0) is 1,x+1,2y-1,z+1,3=0-2,1*x-2,1*2y+2,1*z-2,1*3=0

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expand (1,-2,1)(x+2y-z+3=0)

expand

(1, - 2, 1) (x + 2 y - z + 3 = 0)

1, x + 1, 2 y - 1, z + 1, 3 = 0 - 2, 1 \cdot x - 2, 1 \cdot 2 y + 2, 1 \cdot z - 2, 1 \cdot 3 = 0

Solution steps

(1, - 2, 1) (x + 2 y - z + 3 = 0)

= (1, - 2 \cdot 1,) (x + 2 y - z + 3 \cdot 0 =)

Distribute parentheses

1, x + 1, 2 y + 1, (- z) + 1, 3 = 0 + (- 2, 1) x + (- 2, 1) \cdot 2 y + (- 2, 1) (- z) + (- 2, 1) \cdot 3 = 0

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

1, x + 1, 2 y - 1, z + 1, 3 = 0 - 2, 1 \cdot x - 2, 1 \cdot 2 y + 2, 1 \cdot z - 2, 1 \cdot 3 = 0

\frac{5}{( s - 5 ) ( s + 5 )}

\frac{24 ( n + 1 )}{n}

d x + (\frac{2 x}{y} - y^{2}) d y

4 d - 3 (2 d + 6 = 2 (d + 3))

\frac{( 12 - 3 x ) ^{2}}{2}

What is expand (1,-2,1)(x+2y-z+3=0) ?
The solution to expand (1,-2,1)(x+2y-z+3=0) is 1,x+1,2y-1,z+1,3=0-2,1*x-2,1*2y+2,1*z-2,1*3=0