What is expand ((x+2)*(x+1))/(2x) ?

The solution to expand ((x+2)*(x+1))/(2x) is x/2+3/2+1/x

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expand ((x+2)*(x+1))/(2x)

expand

\frac{( x + 2 ) \cdot ( x + 1 )}{2 x}

\frac{x}{2} + \frac{3}{2} + \frac{1}{x}

Solution steps

\frac{( x + 2 ) ( x + 1 )}{2 x}

Expand

(x + 2) (x + 1) : x^{2} + 3 x + 2

= \frac{x ^{2} + 3 x + 2}{2 x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} + 3 x + 2}{2 x} = \frac{x ^{2}}{2 x} + \frac{3 x}{2 x} + \frac{2}{2 x}

= \frac{x ^{2}}{2 x} + \frac{3 x}{2 x} + \frac{2}{2 x}

Cancel

\frac{x ^{2}}{2 x} : \frac{x}{2}

= \frac{x}{2} + \frac{3 x}{2 x} + \frac{2}{2 x}

Cancel

\frac{3 x}{2 x} : \frac{3}{2}

= \frac{x}{2} + \frac{3}{2} + \frac{2}{2 x}

Divide the numbers:

\frac{2}{2} = 1

= \frac{x}{2} + \frac{3}{2} + \frac{1}{x}

\frac{k - 5}{k ( 5 k + 1 )}

\frac{1}{( ( s ^{2} + 2 s + 1 ) ( s + 1 ) )}

(1 + x + x^{2})^{9}

f (- 4 + h, - 6 + k) - f (- 4, - 6)

(- 2, - 1) - (x, x - 4)

What is expand ((x+2)*(x+1))/(2x) ?
The solution to expand ((x+2)*(x+1))/(2x) is x/2+3/2+1/x