What is expand (-5x-3)(2x+1)'' ?

The solution to expand (-5x-3)(2x+1)'' is -5x(2x+1)''-3(2x+1)''

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expand (-5x-3)(2x+1)''

expand

(- 5 x - 3) (2 x + 1)^{''}

- 5 x (2 x + 1)'' - 3 (2 x + 1)''

Solution steps

(- 5 x - 3) (2 x + 1)^{''}

Apply the distributive law:

a (b - c) = ab - a c

a = (2 x + 1)^{''}, b = - 5 x, c = 3

= (2 x + 1)^{^{''}} (- 5 x) - (2 x + 1)^{^{''}} 3

Apply minus-plus rules

+ (- a) = - a

= - 5 x (2 x + 1)^{^{''}} - 3 (2 x + 1)^{^{''}}

7 + \frac{1}{5}

5 a^{6 - 1}

t^{(x^{2} - x + 2) d x}

π (x + 1 + 6)^{2}

\frac{( y - 3 ) ^{2}}{3}

What is expand (-5x-3)(2x+1)'' ?
The solution to expand (-5x-3)(2x+1)'' is -5x(2x+1)''-3(2x+1)''