What is expand (2x-5x^2)(7x^3-3x)' ?

The solution to expand (2x-5x^2)(7x^3-3x)' is 2x(7x^3-3x)'-5x^2(7x^3-3x)'

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expand (2x-5x^2)(7x^3-3x)'

expand

(2 x - 5 x^{2}) (7 x^{3} - 3 x)^{'}

2 x (7 x^{3} - 3 x)' - 5 x^{2} (7 x^{3} - 3 x)'

Solution steps

(2 x - 5 x^{2}) (7 x^{3} - 3 x)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (7 x^{3} - 3 x)^{'}, b = 2 x, c = 5 x^{2}

= (7 x^{3} - 3 x)^{^{'}} 2 x - (7 x^{3} - 3 x)^{^{'}} 5 x^{2}

= 2 x (7 x^{3} - 3 x)^{^{'}} - 5 x^{2} (7 x^{3} - 3 x)^{^{'}}

y (4, - 4) (1, 1)

- \frac{2 x}{( x + 1 ) ( - x + 1 )}

\frac{24 ( 2 x ^{2} + 3 x + 1 )}{x}

\frac{( x - 1 ) ^{2}}{12}

(1 + 1)^{n}

What is expand (2x-5x^2)(7x^3-3x)' ?
The solution to expand (2x-5x^2)(7x^3-3x)' is 2x(7x^3-3x)'-5x^2(7x^3-3x)'