What is expand ([5(x-h)]-[5x^2])/h ?

The solution to expand ([5(x-h)]-[5x^2])/h is (5x)/h-5-(5x^2)/h

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expand ([5(x-h)]-[5x^2])/h

expand

\frac{[ 5 ( x - h ) ] - [ 5 x ^{2} ]}{h}

\frac{5 x}{h} - 5 - \frac{5 x ^{2}}{h}

Solution steps

\frac{( 5 ( x - h ) ) - ( 5 x ^{2} )}{h}

Remove parentheses:

(a) = a

= \frac{5 ( x - h ) - 5 x ^{2}}{h}

Expand

5 (x - h) - 5 x^{2} : 5 x - 5 h - 5 x^{2}

= \frac{5 x - 5 h - 5 x ^{2}}{h}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{5 x - 5 h - 5 x ^{2}}{h} = \frac{5 x}{h} - \frac{5 h}{h} - \frac{5 x ^{2}}{h}

= \frac{5 x}{h} - \frac{5 h}{h} - \frac{5 x ^{2}}{h}

Cancel

\frac{5 h}{h} : 5

= \frac{5 x}{h} - 5 - \frac{5 x ^{2}}{h}

(2^{6})^{x + 3}

d x (x ln (x) - x)

\frac{f ( x + h ) - x + 6}{h}

- \frac{( x - 20 ) ^{2}}{40}

sin (5 (x - \frac{5 π}{7}))

What is expand ([5(x-h)]-[5x^2])/h ?
The solution to expand ([5(x-h)]-[5x^2])/h is (5x)/h-5-(5x^2)/h