What is expand 1/((x+h-3)(x-3)) ?

The solution to expand 1/((x+h-3)(x-3)) is 1/(xh+x^2-6x-3h+9)

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expand 1/((x+h-3)(x-3))

expand

\frac{1}{( x + h - 3 ) ( x - 3 )}

\frac{1}{x h + x ^{2} - 6 x - 3 h + 9}

Solution steps

\frac{1}{( x + h - 3 ) ( x - 3 )}

Expand

(x + h - 3) (x - 3) : x h + x^{2} - 6 x - 3 h + 9

= \frac{1}{x h + x ^{2} - 6 x - 3 h + 9}

\frac{4 π ( r + 2 ) ^{2}}{3}

(9 t^{2} + 4) t^{2} + 1

\frac{4}{3} x (3, - 2)

\frac{x ^{2} + 1}{x ^{2} ( x + 1 ) ^{2}}

\frac{- 84 x + 372}{7 ( x - 3 ) ( x - 4 )}

What is expand 1/((x+h-3)(x-3)) ?
The solution to expand 1/((x+h-3)(x-3)) is 1/(xh+x^2-6x-3h+9)