What is expand (e^{3x}-4)(e^{3x}+6) ?

The solution to expand (e^{3x}-4)(e^{3x}+6) is e^{6x}+2e^{3x}-24

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expand (e^{3x}-4)(e^{3x}+6)

expand

(e^{3 x} - 4) (e^{3 x} + 6)

e^{6 x} + 2 e^{3 x} - 24

Solution steps

(e^{3 x} - 4) (e^{3 x} + 6)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = e^{3 x}, b = - 4, c = e^{3 x}, d = 6

= e^{3 x} e^{3 x} + e^{3 x} \cdot 6 + (- 4) e^{3 x} + (- 4) \cdot 6

Apply minus-plus rules

+ (- a) = - a

= e^{3 x} e^{3 x} + 6 e^{3 x} - 4 e^{3 x} - 4 \cdot 6

Simplify

e^{3 x} e^{3 x} + 6 e^{3 x} - 4 e^{3 x} - 4 \cdot 6 : e^{6 x} + 2 e^{3 x} - 24

= e^{6 x} + 2 e^{3 x} - 24

\frac{x ( - x + 1 ) ^{3}}{3}

(1 - u^{2})^{2} u^{2} - d u

(1 + 1 + 1 = 0,) (1 + 2 + 3 = 0)

52 (x^{'} + h (x))^{2}

\frac{1}{x ^{2} ( x + a )}

What is expand (e^{3x}-4)(e^{3x}+6) ?
The solution to expand (e^{3x}-4)(e^{3x}+6) is e^{6x}+2e^{3x}-24