What is expand ,(8x^2-7x+8)-(4x^2-3x+3) ?

The solution to expand ,(8x^2-7x+8)-(4x^2-3x+3) is 4x^2-4x+5

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expand ,(8x^2-7x+8)-(4x^2-3x+3)

expand

(8 x^{2} - 7 x + 8) - (4 x^{2} - 3 x + 3)

4 x^{2} - 4 x + 5

Solution steps

(8 x^{2} - 7 x + 8) - (4 x^{2} - 3 x + 3)

Apply rule:

(a) = a

(8 x^{2} - 7 x + 8) = 8 x^{2} - 7 x + 8

= 8 x^{2} - 7 x + 8 - (4 x^{2} - 3 x + 3)

Expand

- (4 x^{2} - 3 x + 3) : - 4 x^{2} + 3 x - 3

= 8 x^{2} - 7 x + 8 - 4 x^{2} + 3 x - 3

Simplify

8 x^{2} - 7 x + 8 - 4 x^{2} + 3 x - 3 : 4 x^{2} - 4 x + 5

= 4 x^{2} - 4 x + 5

(x - \frac{π}{6})^{3}

\frac{1}{30} (e^{8 x} + 8 e^{8 x} x)

(n + 1) - \frac{( n + 1 ) ^{2}}{4 n}

x (2 x - 7 = 1)

(x - 3) e^{\frac{1}{x}}

What is expand ,(8x^2-7x+8)-(4x^2-3x+3) ?
The solution to expand ,(8x^2-7x+8)-(4x^2-3x+3) is 4x^2-4x+5