What is expand ((e^t+e^{-t})e^t)/2 ?

The solution to expand ((e^t+e^{-t})e^t)/2 is (e^{2t})/2+1/2

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expand ((e^t+e^{-t})e^t)/2

expand

\frac{( e ^{t} + e ^{- t} ) e ^{t}}{2}

\frac{e ^{2 t}}{2} + \frac{1}{2}

Solution steps

\frac{( e ^{t} + e ^{- t} ) e ^{t}}{2}

Expand

(e^{t} + e^{- t}) e^{t} : e^{2 t} + 1

= \frac{e ^{2 t} + 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{2 t} + 1}{2} = \frac{e ^{2 t}}{2} + \frac{1}{2}

= \frac{e ^{2 t}}{2} + \frac{1}{2}

\frac{8}{6}

3 x^{2} \cdot (1 - 2 ln (x))

(p^{3})^{2}

2 7^{\frac{1}{3}}

y (y^{2} t^{3})

What is expand ((e^t+e^{-t})e^t)/2 ?
The solution to expand ((e^t+e^{-t})e^t)/2 is (e^{2t})/2+1/2