What is expand (2x+2y+2z)(2xe^z+2ye^z) ?

The solution to expand (2x+2y+2z)(2xe^z+2ye^z) is 4e^zx^2+8e^zxy+4e^zy^2+4e^zxz+4e^zyz

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expand (2x+2y+2z)(2xe^z+2ye^z)

expand

(2 x + 2 y + 2 z) (2 x e^{z} + 2 y e^{z})

4 e^{z} x^{2} + 8 e^{z} x y + 4 e^{z} y^{2} + 4 e^{z} x z + 4 e^{z} yz

Solution steps

(2 x + 2 y + 2 z) (2 x e^{z} + 2 y e^{z})

= (2 x + 2 y + 2 z) (2 e^{z} x + 2 e^{z} y)

Distribute parentheses

= 2 x \cdot 2 x e^{z} + 2 x \cdot 2 y e^{z} + 2 y \cdot 2 x e^{z} + 2 y \cdot 2 y e^{z} + 2 z \cdot 2 x e^{z} + 2 z \cdot 2 y e^{z}

= 2 \cdot 2 e^{z} xx + 2 \cdot 2 e^{z} x y + 2 \cdot 2 e^{z} x y + 2 \cdot 2 e^{z} yy + 2 \cdot 2 e^{z} x z + 2 \cdot 2 e^{z} yz

Simplify

2 \cdot 2 e^{z} xx + 2 \cdot 2 e^{z} x y + 2 \cdot 2 e^{z} x y + 2 \cdot 2 e^{z} yy + 2 \cdot 2 e^{z} x z + 2 \cdot 2 e^{z} yz : 4 e^{z} x^{2} + 8 e^{z} x y + 4 e^{z} y^{2} + 4 e^{z} x z + 4 e^{z} yz

= 4 e^{z} x^{2} + 8 e^{z} x y + 4 e^{z} y^{2} + 4 e^{z} x z + 4 e^{z} yz

\frac{6.3223 ( s + 1.4235 ) ^{2}}{s}

\frac{1}{s ^{2} ( s - 4 )}

(y - x) (- 8, - 2, - 7)

\frac{5 ( 2 + 2 )}{2}

\frac{d}{d t} ((x) (π - t))

What is expand (2x+2y+2z)(2xe^z+2ye^z) ?
The solution to expand (2x+2y+2z)(2xe^z+2ye^z) is 4e^zx^2+8e^zxy+4e^zy^2+4e^zxz+4e^zyz