What is expand 3((x-3)(x+2)(x-4)) ?

The solution to expand 3((x-3)(x+2)(x-4)) is 3x^3-15x^2-6x+72

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expand 3((x-3)(x+2)(x-4))

expand

3 ((x - 3) (x + 2) (x - 4))

3 x^{3} - 15 x^{2} - 6 x + 72

Solution steps

3 ((x - 3) (x + 2) (x - 4))

Remove parentheses:

(a) = a

= 3 (x - 3) (x + 2) (x - 4)

Expand

(x - 3) (x + 2) : x^{2} - x - 6

= 3 (x^{2} - x - 6) (x - 4)

Expand

(x^{2} - x - 6) (x - 4) : x^{3} - 5 x^{2} - 2 x + 24

= 3 (x^{3} - 5 x^{2} - 2 x + 24)

Expand

3 (x^{3} - 5 x^{2} - 2 x + 24) : 3 x^{3} - 15 x^{2} - 6 x + 72

= 3 x^{3} - 15 x^{2} - 6 x + 72

\frac{( - 6 + n ) ( 6 + n )}{4}

t esc a l o n (t - 1)

- 9 (2 π + (π))

(s + 1 - 700 πj) (s + 1 + 700 πj)

(x^{2} y - x) d y

What is expand 3((x-3)(x+2)(x-4)) ?
The solution to expand 3((x-3)(x+2)(x-4)) is 3x^3-15x^2-6x+72