What is expand (sin(θ)-2rcos^2(θ))dr ?

The solution to expand (sin(θ)-2rcos^2(θ))dr is sin(θ)dr-2rcos^2(θ)dr

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expand (sin(θ)-2rcos^2(θ))dr

expand

(sin (θ) - 2 r cos^{2} (θ)) d r

sin (θ) d r - 2 r cos^{2} (θ) d r

Solution steps

(sin (θ) - 2 r cos^{2} (θ)) d r

Apply the distributive law:

a (b - c) = ab - a c

a = d r, b = sin (θ), c = 2 r cos^{2} (θ)

= d r sin (θ) - d r \cdot 2 r cos^{2} (θ)

= sin (θ) d r - 2 r cos^{2} (θ) d r

0.27567 4^{2}

8 \cdot \frac{32}{y} + 8 y

(1.2) (3 x - 4 y - 20 = 0)

2 (n (n + 1) (2 n + 1))

3 (2 - x + 6 = 0)

What is expand (sin(θ)-2rcos^2(θ))dr ?
The solution to expand (sin(θ)-2rcos^2(θ))dr is sin(θ)dr-2rcos^2(θ)dr