What is factor x^4-4x^3+7x^2-12x+12 ?

The solution to factor x^4-4x^3+7x^2-12x+12 is (x-2)^2(x^2+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor x^4-4x^3+7x^2-12x+12

factor

x^{4} - 4 x^{3} + 7 x^{2} - 12 x + 12

(x - 2)^{2} (x^{2} + 3)

Solution steps

x^{4} - 4 x^{3} + 7 x^{2} - 12 x + 12

Use the rational root theorem

= (x - 2) \frac{x ^{4} - 4 x ^{3} + 7 x ^{2} - 12 x + 12}{x - 2}

\frac{x ^{4} - 4 x ^{3} + 7 x ^{2} - 12 x + 12}{x - 2} = x^{3} - 2 x^{2} + 3 x - 6

= (x - 2) (x^{3} - 2 x^{2} + 3 x - 6)

Factor

x^{3} - 2 x^{2} + 3 x - 6 : (x - 2) (x^{2} + 3)

= (x - 2) (x - 2) (x^{2} + 3)

Apply exponent rule:

aa = a^{2}

(x - 2) (x - 2) = (x - 2)^{2}

= (x - 2)^{2} (x^{2} + 3)

10 x^{2} + 17 x - 20 = 0

3 x^{3} y^{2} + 9 x^{2} y^{2} - 18 x y^{2}

r^{2} - 24 r + 144 = 0

∣ (1 + i) (2 - i) ∣

\frac{7 y}{8} - \frac{3 y}{5} = \frac{11}{10}

What is factor x^4-4x^3+7x^2-12x+12 ?
The solution to factor x^4-4x^3+7x^2-12x+12 is (x-2)^2(x^2+3)