What is expand ((-2y+2)^3)/3 ?

The solution to expand ((-2y+2)^3)/3 is -(8y^3)/3+8y^2-8y+8/3

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expand ((-2y+2)^3)/3

expand

\frac{( - 2 y + 2 ) ^{3}}{3}

- \frac{8 y ^{3}}{3} + 8 y^{2} - 8 y + \frac{8}{3}

Solution steps

\frac{( - 2 y + 2 ) ^{3}}{3}

(- 2 y + 2)^{3} = - 8 y^{3} + 24 y^{2} - 24 y + 8

= \frac{( - 8 y ^{3} + 24 y ^{2} - 24 y + 8 )}{3}

Remove parentheses:

(- a) = - a

= \frac{- 8 y ^{3} + 24 y ^{2} - 24 y + 8}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 8 y ^{3} + 24 y ^{2} - 24 y + 8}{3} = - \frac{8 y ^{3}}{3} + \frac{24 y ^{2}}{3} - \frac{24 y}{3} + \frac{8}{3}

= - \frac{8 y ^{3}}{3} + \frac{24 y ^{2}}{3} - \frac{24 y}{3} + \frac{8}{3}

Divide the numbers:

\frac{24}{3} = 8

= - \frac{8 y ^{3}}{3} + 8 y^{2} - 8 y + \frac{8}{3}

e^{x} (- 2 (- e^{- x} x - e^{- x}))

(\frac{1}{x - 2})^{2} + 2

- 3 (x - 2 = 9 x + 16 - 4 x)

(x^{4} + y^{2}) d x + (2 x y + y^{3}) d y

What is expand ((-2y+2)^3)/3 ?
The solution to expand ((-2y+2)^3)/3 is -(8y^3)/3+8y^2-8y+8/3