What is the d/(dy)((x)(24x^2+2y-6)) ?

The d/(dy)((x)(24x^2+2y-6)) is 2x

What is the first d/(dy)((x)(24x^2+2y-6)) ?

The first d/(dy)((x)(24x^2+2y-6)) is 2x

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\frac{d}{d y} ((x) (24 x^{2} + 2 y - 6))

2 x

Solution steps

\frac{d}{d y} ((x) (24 x^{2} + 2 y - 6))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} (24 x^{2} + 2 y - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{d}{d y} (24 x^{2}) + \frac{d}{d y} (2 y) - \frac{d}{d y} (6))

\frac{d}{d y} (24 x^{2}) = 0

\frac{d}{d y} (2 y) = 2

\frac{d}{d y} (6) = 0

= x (0 + 2 - 0)

Simplify

= 2 x

395 X 13

\frac{V ( 2 π - φ )}{( 2 π - 1 )}

s q u a re x (2 x + 1)

\frac{x ^{2} - x}{( x - 2 ) ^{2}}

\frac{5 ( 2 x + 3 )}{2 ( 4 x - 5 )}

What is the d/(dy)((x)(24x^2+2y-6)) ?
The d/(dy)((x)(24x^2+2y-6)) is 2x
What is the first d/(dy)((x)(24x^2+2y-6)) ?
The first d/(dy)((x)(24x^2+2y-6)) is 2x