What is expand 9x^2(3/(3x+3)) ?

The solution to expand 9x^2(3/(3x+3)) is (9x^2)/(x+1)

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expand 9x^2(3/(3x+3))

expand

9 x^{2} (\frac{3}{3 x + 3})

\frac{9 x ^{2}}{x + 1}

Solution steps

9 x^{2} (\frac{3}{3 x + 3})

Remove parentheses:

(a) = a

= 9 x^{2} \frac{3}{3 x + 3}

\frac{3}{3 x + 3} = \frac{1}{x + 1}

= 9 \cdot \frac{1}{x + 1} x^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 9 x ^{2}}{x + 1}

Multiply the numbers:

1 \cdot 9 = 9

= \frac{9 x ^{2}}{x + 1}

\frac{s}{( s ^{2} + 4 ) ( s + 1 )}

3 x (x y - 3) d x + (x^{2} + 2 y) d y

\frac{x ^{2} - x - 4}{x ^{2} ( x + 1 )}

(- x + y + z = 3) \cdot (2)

(7 x + 10 = 1, 4) (x - 2 y = 10)

What is expand 9x^2(3/(3x+3)) ?
The solution to expand 9x^2(3/(3x+3)) is (9x^2)/(x+1)