What is expand (5X^2(X^2-6X+2))/4 ?

The solution to expand (5X^2(X^2-6X+2))/4 is (5X^4)/4-(15X^3)/2+(5X^2)/2

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expand (5X^2(X^2-6X+2))/4

expand

\frac{5 X ^{2} ( X ^{2} - 6 X + 2 )}{4}

\frac{5 X ^{4}}{4} - \frac{15 X ^{3}}{2} + \frac{5 X ^{2}}{2}

Solution steps

\frac{5 X ^{2} ( X ^{2} - 6 X + 2 )}{4}

Expand

5 X^{2} (X^{2} - 6 X + 2) : 5 X^{4} - 30 X^{3} + 10 X^{2}

= \frac{5 X ^{4} - 30 X ^{3} + 10 X ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{5 X ^{4} - 30 X ^{3} + 10 X ^{2}}{4} = \frac{5 X ^{4}}{4} - \frac{30 X ^{3}}{4} + \frac{10 X ^{2}}{4}

= \frac{5 X ^{4}}{4} - \frac{30 X ^{3}}{4} + \frac{10 X ^{2}}{4}

Cancel

\frac{30 X ^{3}}{4} : \frac{15 X ^{3}}{2}

= \frac{5 X ^{4}}{4} - \frac{15 X ^{3}}{2} + \frac{10 X ^{2}}{4}

Cancel

\frac{10 X ^{2}}{4} : \frac{5 X ^{2}}{2}

= \frac{5 X ^{4}}{4} - \frac{15 X ^{3}}{2} + \frac{5 X ^{2}}{2}

c^{2} (Δ x + c)^{2}

\frac{3 x ^{2} - 2}{x ( x - 1 )}

lo g_{e} (1 - x)

5.8 sin (\frac{π}{6} (x - 2)) + 9.2

\frac{( x + 4 ) ( x - 1 )}{x - 4}

What is expand (5X^2(X^2-6X+2))/4 ?
The solution to expand (5X^2(X^2-6X+2))/4 is (5X^4)/4-(15X^3)/2+(5X^2)/2