What is expand ((2x-1)(2x+1))/2 ?

The solution to expand ((2x-1)(2x+1))/2 is 2x^2-1/2

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expand ((2x-1)(2x+1))/2

expand

\frac{( 2 x - 1 ) ( 2 x + 1 )}{2}

2 x^{2} - \frac{1}{2}

Solution steps

\frac{( 2 x - 1 ) ( 2 x + 1 )}{2}

Expand

(2 x - 1) (2 x + 1) : 4 x^{2} - 1

= \frac{4 x ^{2} - 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 1}{2} = \frac{4 x ^{2}}{2} - \frac{1}{2}

= \frac{4 x ^{2}}{2} - \frac{1}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 x^{2} - \frac{1}{2}

\frac{( - a + 1 )}{a ( a - 2 ) ( a + 1 )}

\frac{( 2 s + 1 ) ( s - 8 )}{s}

(1 + y) e^{y} - x

\frac{2}{x ( x - 1 ) ( x - 2 )}

e^{x} (x + 9)

What is expand ((2x-1)(2x+1))/2 ?
The solution to expand ((2x-1)(2x+1))/2 is 2x^2-1/2