What is expand (((3-x))/9)^2 ?

The solution to expand (((3-x))/9)^2 is (x^2)/(81)-(2x)/(27)+1/9

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expand (((3-x))/9)^2

expand

(\frac{( 3 - x )}{9})^{2}

\frac{x ^{2}}{81} - \frac{2 x}{27} + \frac{1}{9}

Solution steps

(\frac{3 - x}{9})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 - x ) ^{2}}{9 ^{2}}

(3 - x)^{2} = 9 - 6 x + x^{2}

= \frac{9 - 6 x + x ^{2}}{9 ^{2}}

9^{2} = 81

= \frac{9 - 6 x + x ^{2}}{81}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 - 6 x + x ^{2}}{81} = \frac{9}{81} - \frac{6 x}{81} + \frac{x ^{2}}{81}

= \frac{9}{81} - \frac{6 x}{81} + \frac{x ^{2}}{81}

Cancel

\frac{9}{81} : \frac{1}{9}

= \frac{1}{9} - \frac{6 x}{81} + \frac{x ^{2}}{81}

Cancel

\frac{6 x}{81} : \frac{2 x}{27}

= \frac{1}{9} - \frac{2 x}{27} + \frac{x ^{2}}{81}

Rewrite in standard form

= \frac{x ^{2}}{81} - \frac{2 x}{27} + \frac{1}{9}

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What is expand (((3-x))/9)^2 ?
The solution to expand (((3-x))/9)^2 is (x^2)/(81)-(2x)/(27)+1/9