What is expand-2(3x+4y=19) ?

The solution to expand-2(3x+4y=19) is -6x-8y=19

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expand-2(3x+4y=19)

expand

- 2 (3 x + 4 y = 19)

- 6 x - 8 y = 19

Solution steps

- 2 (3 x + 4 y = 19)

= - 2 (3 x + 4 \cdot 19 = y)

Apply the distributive law:

a (b + c) = ab + a c

a = - 2, b = 3 x, c = 4 y = 19

- 2 \cdot 3 x + (- 2) \cdot 4 y = 19

Apply minus-plus rules

+ (- a) = - a

- 2 \cdot 3 x - 2 \cdot 4 y = 19

Expand

- 2 \cdot 3 x - 2 \cdot 4 y : - 6 x - 8 y

- 6 x - 8 y = 19

(lo g_{e} (1 + 2))^{2}

(3 e^{- 5 t} - 15 t e^{- 5 t})^{2}

3 x + 6 x + 12

(x + y^{^{'}}) (x + z)

\frac{n + 1}{( n + 2 ) ( n )}