What are the solutions to the equation y^2-6y+1=0 ?

The solutions to the equation y^2-6y+1=0 are y=3+2sqrt(2),y=3-2sqrt(2)

Find the zeros of y^2-6y+1=0

The zeros of y^2-6y+1=0 are y=3+2sqrt(2),y=3-2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 6 y + 1 = 0

y = 3 + 22, y = 3 - 22

Decimal Notation

y = 5.82842 \dots, y = 0.17157 \dots

Solution steps

y^{2} - 6 y + 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 1 = 42

y_{1, 2} = \frac{- ( - 6 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 4 2}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 4 2}{2 \cdot 1}

y = \frac{- ( - 6 ) + 4 2}{2 \cdot 1} : 3 + 22

y = \frac{- ( - 6 ) - 4 2}{2 \cdot 1} : 3 - 22

The solutions to the quadratic equation are:

y = 3 + 22, y = 3 - 22

\frac{6 - ( - 8 )}{4 - ( - 3 )}

2 = \frac{c}{( 2 \cdot 0.1 \cdot ( \frac{π ^{2}}{10} ) )}

172 8^{\frac{1}{3}}

10 = - 4 x + 3 x^{2}

∣ x - 9 ∣ = - 8

What are the solutions to the equation y^2-6y+1=0 ?
The solutions to the equation y^2-6y+1=0 are y=3+2sqrt(2),y=3-2sqrt(2)
Find the zeros of y^2-6y+1=0
The zeros of y^2-6y+1=0 are y=3+2sqrt(2),y=3-2sqrt(2)