What is expand (3(-3y+12))/(16) ?

The solution to expand (3(-3y+12))/(16) is -(9y)/(16)+9/4

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expand (3(-3y+12))/(16)

expand

\frac{3 ( - 3 y + 12 )}{16}

- \frac{9 y}{16} + \frac{9}{4}

Solution steps

\frac{3 ( - 3 y + 12 )}{16}

Expand

3 (- 3 y + 12) : - 9 y + 36

= \frac{- 9 y + 36}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 9 y + 36}{16} = - \frac{9 y}{16} + \frac{36}{16}

= - \frac{9 y}{16} + \frac{36}{16}

Cancel

\frac{36}{16} : \frac{9}{4}

= - \frac{9 y}{16} + \frac{9}{4}

\frac{6 x - 2}{( x - 3 ) ( x + 1 )}

6 a 2

\frac{x ^{2} + C}{e ^{x} ( 2 x + 3 )}

(5 cos (π x) + sin (5 π x))^{2}

y (2 x y^{'} (x) - y)

What is expand (3(-3y+12))/(16) ?
The solution to expand (3(-3y+12))/(16) is -(9y)/(16)+9/4