What is the d/(dt)((a)(300+t)^2) ?

The d/(dt)((a)(300+t)^2) is 2a(300+t)

What is the first d/(dt)((a)(300+t)^2) ?

The first d/(dt)((a)(300+t)^2) is 2a(300+t)

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\frac{d}{d t} ((a) (300 + t)^{2})

2 a (300 + t)

Solution steps

\frac{d}{d t} ((a) (300 + t)^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a \frac{d}{d t} ((300 + t)^{2})

Apply the chain rule:

2 (300 + t) \frac{d}{d t} (300 + t)

= 2 (300 + t) \frac{d}{d t} (300 + t)

\frac{d}{d t} (300 + t) = 1

= a \cdot 2 (300 + t) \cdot 1

Simplify

= 2 a (300 + t)

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What is the d/(dt)((a)(300+t)^2) ?
The d/(dt)((a)(300+t)^2) is 2a(300+t)
What is the first d/(dt)((a)(300+t)^2) ?
The first d/(dt)((a)(300+t)^2) is 2a(300+t)