What is expand ((3x+2y)(3x-2y))/(36) ?

The solution to expand ((3x+2y)(3x-2y))/(36) is (x^2)/4-(y^2)/9

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expand ((3x+2y)(3x-2y))/(36)

expand

\frac{( 3 x + 2 y ) ( 3 x - 2 y )}{36}

\frac{x ^{2}}{4} - \frac{y ^{2}}{9}

Solution steps

\frac{( 3 x + 2 y ) ( 3 x - 2 y )}{36}

Expand

(3 x + 2 y) (3 x - 2 y) : 9 x^{2} - 4 y^{2}

= \frac{9 x ^{2} - 4 y ^{2}}{36}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{2} - 4 y ^{2}}{36} = \frac{9 x ^{2}}{36} - \frac{4 y ^{2}}{36}

= \frac{9 x ^{2}}{36} - \frac{4 y ^{2}}{36}

Cancel

\frac{9 x ^{2}}{36} : \frac{x ^{2}}{4}

= \frac{x ^{2}}{4} - \frac{4 y ^{2}}{36}

Cancel

\frac{4 y ^{2}}{36} : \frac{y ^{2}}{9}

= \frac{x ^{2}}{4} - \frac{y ^{2}}{9}

(x + 9 x) e^{x}

\frac{( 2 x + 1 )}{( 4 + x ^{2} ) d x}

(e^{2 x} + 1) (e^{2 x} - 1)

\frac{1}{3 ( x - 5 )}

e x p ress i o n^{0.15} k (x + y)

What is expand ((3x+2y)(3x-2y))/(36) ?
The solution to expand ((3x+2y)(3x-2y))/(36) is (x^2)/4-(y^2)/9