What is expand ln(αe^x+(1-α)e^y) ?

The solution to expand ln(αe^x+(1-α)e^y) is ln(e^xα+e^y-e^yα)

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expand ln(αe^x+(1-α)e^y)

expand

ln (α e^{x} + (1 - α) e^{y})

ln (e^{x} α + e^{y} - e^{y} α)

Solution steps

ln (α e^{x} + (1 - α) e^{y})

Expand

α e^{x} + (1 - α) e^{y} : α e^{x} + e^{y} - e^{y} α

= ln (e^{x} α + e^{y} - e^{y} α)

π (3 x + 2)^{2}

\frac{25}{s ^{2} ( s ^{2} + 2 s + 5 )}

4 (\frac{1}{2})^{3} (- 3 a)

\frac{3}{( s - 2 ) ^{4}}

(6 x^{2} + 7 y sin (2 x)) d x

What is expand ln(αe^x+(1-α)e^y) ?
The solution to expand ln(αe^x+(1-α)e^y) is ln(e^xα+e^y-e^yα)