What is the d/(dt)((x)(5t+e^{-t})) ?

The d/(dt)((x)(5t+e^{-t})) is x(5-e^{-t})

What is the first d/(dt)((x)(5t+e^{-t})) ?

The first d/(dt)((x)(5t+e^{-t})) is x(5-e^{-t})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} ((x) (5 t + e^{- t}))

x (5 - e^{- t})

Solution steps

\frac{d}{d t} ((x) (5 t + e^{- t}))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d t} (5 t + e^{- t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{d}{d t} (5 t) + \frac{d}{d t} (e^{- t}))

\frac{d}{d t} (5 t) = 5

\frac{d}{d t} (e^{- t}) = - e^{- t}

= x (5 - e^{- t})

\frac{2 s ( s + 1 )}{s ^{2} + 52 s + 1}

\frac{6}{5 ( x - 6 )}

π (1 - \frac{x}{3})^{2}

2 (8 x - 15 y = - 30)

\frac{3 k ( k + 1 )}{2}

What is the d/(dt)((x)(5t+e^{-t})) ?
The d/(dt)((x)(5t+e^{-t})) is x(5-e^{-t})
What is the first d/(dt)((x)(5t+e^{-t})) ?
The first d/(dt)((x)(5t+e^{-t})) is x(5-e^{-t})