What is expand ,5((3+2i)+(3+2i)(1+5i)) ?

The solution to expand ,5((3+2i)+(3+2i)(1+5i)) is -20+95i

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expand ,5((3+2i)+(3+2i)(1+5i))

expand

5 ((3 + 2 i) + (3 + 2 i) (1 + 5 i))

- 20 + 95 i

Solution steps

5 ((3 + 2 i) + (3 + 2 i) (1 + 5 i))

Simplify

(3 + 2 i) + (3 + 2 i) (1 + 5 i) : 3 + 2 i + (3 + 2 i) (1 + 5 i)

= 5 (3 + 2 i + (3 + 2 i) (1 + 5 i))

Apply the distributive law:

m (a + b + c) = ma + mb + m c

5 (3 + 2 i + (3 + 2 i) (1 + 5 i)) = 5 \cdot 3 + 5 \cdot 2 i + 5 (3 + 2 i) (1 + 5 i)

= 5 \cdot 3 + 5 \cdot 2 i + 5 (3 + 2 i) (1 + 5 i)

Simplify

5 \cdot 3 + 5 \cdot 2 i + 5 (3 + 2 i) (1 + 5 i) : 95 i - 20

= 95 i - 20

Rewrite in standard complex form:

- 20 + 95 i

= - 20 + 95 i

4 (m^{3} n) 5

\frac{3 x + 2}{( x + 1 ) ^{3}}

d 11 \cdot 3

\frac{35 x}{( x - 7 ) ( 8 x - 24 )}

\frac{5 ( 11 + 13 )}{3}

What is expand ,5((3+2i)+(3+2i)(1+5i)) ?
The solution to expand ,5((3+2i)+(3+2i)(1+5i)) is -20+95i