What is expand-9(x+Δx)^2 ?

The solution to expand-9(x+Δx)^2 is -9x^2-18Δx^2-9Δ^2x^2

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expand-9(x+Δx)^2

expand

- 9 (x + Δ x)^{2}

- 9 x^{2} - 18Δ x^{2} - 9 Δ^{2} x^{2}

Solution steps

- 9 (x + Δ x)^{2}

(x + Δ x)^{2} = x^{2} + 2Δ x^{2} + Δ^{2} x^{2}

= - 9 (x^{2} + 2Δ x^{2} + Δ^{2} x^{2})

Distribute parentheses

= (- 9) x^{2} + (- 9) \cdot 2Δ x^{2} + (- 9) Δ^{2} x^{2}

Apply minus-plus rules

+ (- a) = - a

= - 9 x^{2} - 9 \cdot 2Δ x^{2} - 9 Δ^{2} x^{2}

Multiply the numbers:

9 \cdot 2 = 18

= - 9 x^{2} - 18Δ x^{2} - 9 Δ^{2} x^{2}

(0.05 x + 0.06 y = 38, 40) (x + y = 69000)

(1 - x - x^{2})^{5}

(- 24 - 4 D + 2 E = 0,) - (- 12 - 2 D + 6 E = 0)

(12 d^{7} - 6 e^{11})^{2}

lo g_{2} (4 x) y

What is expand-9(x+Δx)^2 ?
The solution to expand-9(x+Δx)^2 is -9x^2-18Δx^2-9Δ^2x^2