What is the d/(dt)((θ)(5+2sin(3θ))) ?

The d/(dt)((θ)(5+2sin(3θ))) is 5+2sin(3t)+6tcos(3t)

What is the first d/(dt)((θ)(5+2sin(3θ))) ?

The first d/(dt)((θ)(5+2sin(3θ))) is 5+2sin(3t)+6tcos(3t)

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\frac{d}{d t} ((t) (5 + 2 sin (3 t)))

5 + 2 sin (3 t) + 6 t cos (3 t)

Solution steps

\frac{d}{d t} ((t) (5 + 2 sin (3 t)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = 5 + 2 sin (3 t)

= \frac{d t}{d t} (5 + 2 sin (3 t)) + \frac{d}{d t} (5 + 2 sin (3 t)) t

\frac{d t}{d t} = 1

\frac{d}{d t} (5 + 2 sin (3 t)) = 6 cos (3 t)

= 1 \cdot (5 + 2 sin (3 t)) + 6 cos (3 t) t

Simplify

= 5 + 2 sin (3 t) + 6 t cos (3 t)

6 (4 ln (2) - 1)

\frac{2 ( x + 2 )}{x + 3}

e^{5 x} (2 x - 1)

- 5 (2 e - 3 d + 1 = 91)

\frac{n ^{2} ( n + 1 ) ^{2}}{2}

What is the d/(dt)((θ)(5+2sin(3θ))) ?
The d/(dt)((θ)(5+2sin(3θ))) is 5+2sin(3t)+6tcos(3t)
What is the first d/(dt)((θ)(5+2sin(3θ))) ?
The first d/(dt)((θ)(5+2sin(3θ))) is 5+2sin(3t)+6tcos(3t)