What is expand (3y^4(2u^5-1))/u ?

The solution to expand (3y^4(2u^5-1))/u is 6y^4u^4-(3y^4)/u

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expand (3y^4(2u^5-1))/u

expand

\frac{3 y ^{4} ( 2 u ^{5} - 1 )}{u}

6 y^{4} u^{4} - \frac{3 y ^{4}}{u}

Solution steps

\frac{3 y ^{4} ( 2 u ^{5} - 1 )}{u}

Expand

3 y^{4} (2 u^{5} - 1) : 6 y^{4} u^{5} - 3 y^{4}

= \frac{6 y ^{4} u ^{5} - 3 y ^{4}}{u}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 y ^{4} u ^{5} - 3 y ^{4}}{u} = \frac{6 y ^{4} u ^{5}}{u} - \frac{3 y ^{4}}{u}

= \frac{6 y ^{4} u ^{5}}{u} - \frac{3 y ^{4}}{u}

Cancel

\frac{6 y ^{4} u ^{5}}{u} : 6 y^{4} u^{4}

= 6 y^{4} u^{4} - \frac{3 y ^{4}}{u}

- (x ln (x) - x) (y x)

\frac{2 ( 3 17 - 1 )}{19}

\frac{4 ( x - 4 )}{x ( x + 3 )}

(ln (y) + c) y

(x - 2 y) d x

What is expand (3y^4(2u^5-1))/u ?
The solution to expand (3y^4(2u^5-1))/u is 6y^4u^4-(3y^4)/u