What is expand ((e^8-1)^2)/(4e^8) ?

The solution to expand ((e^8-1)^2)/(4e^8) is (e^8)/4-1/2+1/(4e^8)

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expand ((e^8-1)^2)/(4e^8)

expand

\frac{( e ^{8} - 1 ) ^{2}}{4 e ^{8}}

\frac{e ^{8}}{4} - \frac{1}{2} + \frac{1}{4 e ^{8}}

Decimal Notation

744.73958 \dots

Solution steps

\frac{( e ^{8} - 1 ) ^{2}}{4 e ^{8}}

(e^{8} - 1)^{2} = e^{16} - 2 e^{8} + 1

= \frac{e ^{16} - 2 e ^{8} + 1}{4 e ^{8}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{16} - 2 e ^{8} + 1}{4 e ^{8}} = \frac{e ^{16}}{4 e ^{8}} - \frac{2 e ^{8}}{4 e ^{8}} + \frac{1}{4 e ^{8}}

= \frac{e ^{16}}{4 e ^{8}} - \frac{2 e ^{8}}{4 e ^{8}} + \frac{1}{4 e ^{8}}

Cancel

\frac{e ^{16}}{4 e ^{8}} : \frac{e ^{8}}{4}

= \frac{e ^{8}}{4} - \frac{2 e ^{8}}{4 e ^{8}} + \frac{1}{4 e ^{8}}

Cancel

\frac{2 e ^{8}}{4 e ^{8}} : \frac{1}{2}

= \frac{e ^{8}}{4} - \frac{1}{2} + \frac{1}{4 e ^{8}}

\frac{1}{( s ^{2} + s + 6 ) ^{2}}

\frac{1}{2} (- 2 y + 12 z = 2)

2 (1 - e^{- x^{2} + 1})

\frac{16}{( 2 - x ) ^{2}}

\frac{16.4 - 4 x}{4.1 x ( x - 4.1 )}

What is expand ((e^8-1)^2)/(4e^8) ?
The solution to expand ((e^8-1)^2)/(4e^8) is (e^8)/4-1/2+1/(4e^8)