What is expand ((4x+3)(-4x+3))/(16) ?

The solution to expand ((4x+3)(-4x+3))/(16) is -x^2+9/16

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expand ((4x+3)(-4x+3))/(16)

expand

\frac{( 4 x + 3 ) ( - 4 x + 3 )}{16}

- x^{2} + \frac{9}{16}

Solution steps

\frac{( 4 x + 3 ) ( - 4 x + 3 )}{16}

Expand

(4 x + 3) (- 4 x + 3) : 9 - 16 x^{2}

= \frac{9 - 16 x ^{2}}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 - 16 x ^{2}}{16} = \frac{9}{16} - \frac{16 x ^{2}}{16}

= \frac{9}{16} - \frac{16 x ^{2}}{16}

Divide the numbers:

\frac{16}{16} = 1

= \frac{9}{16} - x^{2}

Rewrite in standard form

= - x^{2} + \frac{9}{16}

(x - 7) e^{2}

\frac{s - 2}{( s + 1 ) ( s + 2 ) ( s + 3 )}

\frac{1}{7 ^{- 2}}

(a - e x) (ey)

\frac{8 ( 5 - y )}{3}

What is expand ((4x+3)(-4x+3))/(16) ?
The solution to expand ((4x+3)(-4x+3))/(16) is -x^2+9/16