What is expand 1/(x^2(-sin(x)+c)) ?

The solution to expand 1/(x^2(-sin(x)+c)) is 1/(-x^2sin(x)+cx^2)

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expand 1/(x^2(-sin(x)+c))

expand

\frac{1}{x ^{2} ( - sin ( x ) + c )}

\frac{1}{- x ^{2} sin ( x ) + c x ^{2}}

Solution steps

\frac{1}{x ^{2} ( - sin ( x ) + c )}

Expand

x^{2} (- sin (x) + c) : - x^{2} sin (x) + c x^{2}

= \frac{1}{- x ^{2} sin ( x ) + c x ^{2}}

- 2 (e^{x} + 1)^{2}

\frac{25}{( s - 1 ) ^{3} ( s + 3 )}

(a + b^{'} + c) x + (a + b + c) y

(2 r^{4} + 8 r^{2} + 1)^{5}

\frac{e ^{x}}{( ( 1 - e ^{x} ) ^{2} )}

What is expand 1/(x^2(-sin(x)+c)) ?
The solution to expand 1/(x^2(-sin(x)+c)) is 1/(-x^2sin(x)+cx^2)