What is expand y(-2x^2y+y^2=1) ?

The solution to expand y(-2x^2y+y^2=1) is -2x^2y^2+y^3=1

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expand y(-2x^2y+y^2=1)

expand

y (- 2 x^{2} y + y^{2} = 1)

- 2 x^{2} y^{2} + y^{3} = 1

Solution steps

y (- 2 x^{2} y + y^{2} = 1)

= y (- 2 x^{2} y + 1 = y^{2})

Apply the distributive law:

a (b + c) = ab + a c

a = y, b = - 2 x^{2} y, c = y^{2} = 1

y (- 2 x^{2} y) + y y^{2} = 1

Apply minus-plus rules

+ (- a) = - a

- 2 x^{2} yy + y y^{2} = 1

Expand

- 2 x^{2} yy + y y^{2} : - 2 x^{2} y^{2} + y^{3}

- 2 x^{2} y^{2} + y^{3} = 1

v_{0} (1 - e^{\frac{1}{t}})

\frac{7 - 4 x}{4 ( x - 1 )}

\frac{1}{2 ( y - 4 )}

sin (2 (x + i y))

\frac{2 ( x - 1 )}{3 - 2 y}

What is expand y(-2x^2y+y^2=1) ?
The solution to expand y(-2x^2y+y^2=1) is -2x^2y^2+y^3=1