What are the solutions to the equation 2x^2+14=0 ?

The solutions to the equation 2x^2+14=0 are x=sqrt(7)i,x=-sqrt(7)i

Find the zeros of 2x^2+14=0

The zeros of 2x^2+14=0 are x=sqrt(7)i,x=-sqrt(7)i

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2 x^{2} + 14 = 0

x = 7 i, x = - 7 i

Solution steps

2 x^{2} + 14 = 0

Move

14

to the right side

2 x^{2} = - 14

Divide both sides by

2

x^{2} = - 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 7, x = - - 7

- 7 = 7 i

- - 7 = - 7 i

x = 7 i, x = - 7 i

\frac{a ^{8}}{a ^{6}}

\frac{9 !}{( 9 - 3 ) ! \cdot 3 !}

5 x^{2} - 38 x + 48 = 0

3 x + 6 = - 4 x - 8

ln ∣ 4 ∣

What are the solutions to the equation 2x^2+14=0 ?
The solutions to the equation 2x^2+14=0 are x=sqrt(7)i,x=-sqrt(7)i
Find the zeros of 2x^2+14=0
The zeros of 2x^2+14=0 are x=sqrt(7)i,x=-sqrt(7)i