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Popular >

expand (ln(1-x)+C)Y

Solution

expand

(ln (1 - x) + C) Y

Solution

Y ln (1 - x) + C Y

Solution steps

(ln (1 - x) + C) Y

= Y (ln (1 - x) + C)

Apply the distributive law:

a (b + c) = ab + a c

a = Y, b = ln (1 - x), c = C

= Y ln (1 - x) + Y C

= Y ln (1 - x) + C Y

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Frequently Asked Questions (FAQ)

What is expand (ln(1-x)+C)Y ?
The solution to expand (ln(1-x)+C)Y is Yln(1-x)+CY