What is expand ((v-1)^3)/(v^2) ?

The solution to expand ((v-1)^3)/(v^2) is v-3+3/v-1/(v^2)

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expand ((v-1)^3)/(v^2)

expand

\frac{( v - 1 ) ^{3}}{v ^{2}}

v - 3 + \frac{3}{v} - \frac{1}{v ^{2}}

Solution steps

\frac{( v - 1 ) ^{3}}{v ^{2}}

(v - 1)^{3} = v^{3} - 3 v^{2} + 3 v - 1

= \frac{v ^{3} - 3 v ^{2} + 3 v - 1}{v ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{v ^{3} - 3 v ^{2} + 3 v - 1}{v ^{2}} = \frac{v ^{3}}{v ^{2}} - \frac{3 v ^{2}}{v ^{2}} + \frac{3 v}{v ^{2}} - \frac{1}{v ^{2}}

= \frac{v ^{3}}{v ^{2}} - \frac{3 v ^{2}}{v ^{2}} + \frac{3 v}{v ^{2}} - \frac{1}{v ^{2}}

Cancel

\frac{v ^{3}}{v ^{2}} : v

= v - \frac{3 v ^{2}}{v ^{2}} + \frac{3 v}{v ^{2}} - \frac{1}{v ^{2}}

Cancel

\frac{3 v ^{2}}{v ^{2}} : 3

= v - 3 + \frac{3 v}{v ^{2}} - \frac{1}{v ^{2}}

Cancel

\frac{3 v}{v ^{2}} : \frac{3}{v}

= v - 3 + \frac{3}{v} - \frac{1}{v ^{2}}

(x - 1) (\cdot + 2)

x^{2} 6^{x} - 64 (6^{x})

\frac{1}{( a + 2 ) ( a - 1 )}

\frac{1}{( s - 2 ) ^{3} ( s - 1 )}

l m (w x) - (3 x + 1) ln (x)

What is expand ((v-1)^3)/(v^2) ?
The solution to expand ((v-1)^3)/(v^2) is v-3+3/v-1/(v^2)