What is expand (x+1)/((2x-3)^2) ?

The solution to expand (x+1)/((2x-3)^2) is (x+1)/(4x^2-12x+9)

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expand (x+1)/((2x-3)^2)

expand

\frac{x + 1}{( 2 x - 3 ) ^{2}}

\frac{x + 1}{4 x ^{2} - 12 x + 9}

Solution steps

\frac{x + 1}{( 2 x - 3 ) ^{2}}

(2 x - 3)^{2} = 4 x^{2} - 12 x + 9

= \frac{x + 1}{4 x ^{2} - 12 x + 9}

\frac{27 ( x + 1 )}{x}

\frac{( d - c ) ( x - a )}{( b - a ) + c}

2.25 (3, 33 x - 4) - 0.25 (2 x - 8)

(3 - 1) + (1 + 3) i

sin (90 (30 - x))

What is expand (x+1)/((2x-3)^2) ?
The solution to expand (x+1)/((2x-3)^2) is (x+1)/(4x^2-12x+9)