What is expand ((3x-1)(x+1))/(2(x-1)) ?

The solution to expand ((3x-1)(x+1))/(2(x-1)) is (3x^2+2x-1)/(2x-2)

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expand ((3x-1)(x+1))/(2(x-1))

expand

\frac{( 3 x - 1 ) ( x + 1 )}{2 ( x - 1 )}

\frac{3 x ^{2} + 2 x - 1}{2 x - 2}

Solution steps

\frac{( 3 x - 1 ) ( x + 1 )}{2 ( x - 1 )}

Expand

2 (x - 1) : 2 x - 2

= \frac{( 3 x - 1 ) ( x + 1 )}{2 x - 2}

Expand

(3 x - 1) (x + 1) : 3 x^{2} + 2 x - 1

= \frac{3 x ^{2} + 2 x - 1}{2 x - 2}

e x p an (3 z^{2} - 2) (z^{2} - 3 z - 4)

\frac{π ( 144 ln ( 6 ) + 1295 )}{144}

9 (x + 3 = 27)

R (w^{2} L C - w L \cdot 2 π)

(- x + 3) - (x^{2} - 9) d x

What is expand ((3x-1)(x+1))/(2(x-1)) ?
The solution to expand ((3x-1)(x+1))/(2(x-1)) is (3x^2+2x-1)/(2x-2)